Related Questions. What is the orbital notation of Cu? In shorthand [Ar] 3d10 4s1 ,in full notation [1s2 

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[ Ar ] 3 d 10 4 s 1. 29 Cu Det är en övergångsmetall , i det periodiska systemet är det i den fjärde Som en relativt mjuk metall är koppar lätt att forma och tåla.

[Ar]3d5 4s1 e. none of these [Ar]3d10 4s1. the electron configuration for silicon is a. 1s2 2s2 2p6 3s2 3p2 b. 1s2 2s2 2p6 3s1 3d2 Identify the specific element that corresponds to each of the following electron configurations: a) [Ar] 3d10, 4s2, 4p b) [Ar] 3d10 4s c) [Ne] 3s d) [Ar] 3d5, 4s1 e) [Ar] 3d10, 4s2, 4p 8.

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[He] 2s22p3 13. [He] 2s22p5 14. [Kr] 4d10 5s2 5p6 19. [Rn] 5f6 782 21. [Ne] 382 3p4 23. [Xe] 4f14 6s2 24. [Ar]3d10 452 27.

Match the following elements with the corresponding ground state electronic configurations: Group of answer choices. Ge [ Choose ] [Ar] 3d10 [Ar] 4s2 3d6 [Ar] 4s2 3d10 4p2 [Ar] 4s2 3d10 [Ar] 3d8 [Xe] 6s2 4f14 5d4 [Ar] 4s2 3d2 [Ar] 4s1 3d5 [Ar] 4s2 3d8

(Ar:18 Kr:36) O 29CU [Ar]3d10 4s1 O 54Xe [Kr]4d10 5s2 5p6 O 50Sn [Kr]4d10 5s2 5p2… 元素铜,[Ar] 3d10 4s1. 一价铜离子(亚铜离子)Cu+, [Ar] 3d10. 二价铜离子 Cu2+, [Ar] 3d9. 按照洪特规则,的确二价铜离子不如符合“全满”条件的亚铜离子稳定。 但是铜离子更常见,这是为啥呢? 首先,我们来解释为什么在大多数溶液中,铜离子比亚铜离子稳定。 29Cu = [Ar] 3d10 4s1 33As = [Ar]3d10 4s2 4p3 keilakayet keilakayet La configuración electrónica de los elementos es: 29Cu: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁹ .

Ar 3d10 4s1

Because d5 (just half filled) and d10 (completely filled) configurations are more stable compared to d4 and d9 configurations, electronic transition occurs from s to d subshells in these elements (due to exchange energy effect and symmetry of orbitals), i.e. Cr: 4s23d4 → 4s13d5 and Cu : 4s2 3d9 → 4s1 3d10. s- electrons being less in number have little effect in this pursuit.

Zinc [Ar] 3d10 4s2. Gallium [Ar] 3d10 4s2 4p1. Germanium [Ar] 3d10 4s2 4p2. Arsenic [Ar] 3d10 4s2 4p3.

Ar 3d10 4s1

Selenium. 78.96 [Ar] 4s2 Example like copper i ion cu+, the valence electron is [Ar] 3d10 but not 3d8 4s2. This is because the 4s1 of the element copper have the higher energy than the 3d10 thus 4s1 is eliminated. (cu=[Ar] 3d10 4s1) Electron configuration of Selenium is [Ar] 3d10 4s2 4p4. Possible oxidation states are +4,6/-2. Electron Configuration.
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Skjut 2.

This is equivalent to "Choice E". (The configuration associated with copper in copper compounds is not necessarily the same.) [Ar] 4s1 3d10. Niobium (Nb) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d4 [Kr] 5s1 4d4.
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Br: [Kr]4s23d104p7 C. Actually, the correct electron configuration for copper (I) is [ Ar] 4s1 3d10, not [Ar] 4s2 3d9. [Ar]4s24p63d3 c. [Ar]4s13d8 C. Al (алюминий).

Chromium [Ar] 3d5 4s1. Manganese [Ar] 4s2 3d5. Iron [Ar] 4s2 3d6.

Click here👆to get an answer to your question ️ [Ar] 3d^10 4s^1 electronic configuration belongs to :

Mg. [Ne] ↑↑. B. [Ne] ↑↓.

[Ar] 4s2 3d7. 1s 2s 2p 30. 3: Dans  [Ar] 4s2 3d9. D. [Ar] 4s1 3d10. 4. 0.